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Kryger [21]
2 years ago
15

45 points! x+1(8+5)+y2-3(x3+y-4)=36-4+x7-y-1 pls i need help now!

Mathematics
1 answer:
Nadya [2.5K]2 years ago
3 0
The answer is X=-2/5
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28÷7+(-19+10)(-4) <br>does anyone know how to do this <br>​
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Pemdas
28/7 + (-19+10)(-4)
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Simplify.<br> c) <img src="https://tex.z-dn.net/?f=%5Csqrt%7B25%2B10%5Csqrt%7B5%7D%20%2B5%20%7D" id="TexFormula1" title="\sqrt{2
tatyana61 [14]

Answer:

  • 5+\sqrt{5}

Step-by-step explanation:

Both are essentially same questions, considering 30 = 25 + 5.

<u>Solving c)</u>

  • \sqrt{25+10\sqrt{5} +5} =
  • \sqrt{5^2+2*5*\sqrt{5} +(\sqrt{5} )^2} =
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  • 5+\sqrt{5}
8 0
2 years ago
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Please explain, True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6
Alika [10]
The answer is true.....
3 0
3 years ago
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What do I’m supposed to do ?
vlabodo [156]

Answer: okay so first solve for x which is going to be x=10

Step-by-step explanation:

3 0
2 years ago
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I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

4 0
2 years ago
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