What's a proportion that can be used to find out how many points a student needs to reach 78 percent on a 50 point quiz?

Which ordered pair is a solution to this equation?

hjlf

The answer to this is (11, 1).

4 0

2 years ago

Use the properties of operations to write an expression equivalent to: 4x + 1/2 + 2x - 3

NikAS [45]

Answer:

6x * 1/2 - 3 (* means multiplying)

Step-by-step explanation:

In this problem, you are using communitive property and so you are just changing the problem to an equal situation.

4 0

2 years ago

Read 2 more answers

Help ASAP, really stuck

SpyIntel [72]

The total length of the wire needed to make this shape is 162cm

<h3>Perimeter of a triangle</h3>

The perimeter of a triangle is the sum of the external side of the triangle.

Given the following parameters

Length of one side of the outside shape = 24cm

The side length of the smaller triangle = 24/4 = 6cm

The perimeter of the smallest triangle 3(6) = 18cm

The perimeter of the smaller triangle (at the middle) = 12(3) = 36cm

Total length of wire needed. = 3(24) + 3(18) + 36

Total length of wire needed = 72 + 54 + 36

Total length of wire needed = 162cm

Hence the total length of the wire needed to make this shape is 162cm

Learn more on perimeter of triangle here: brainly.com/question/24382052

#SPJ1

6 0

1 year ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

2 years ago

Deshaun's gas tank is 1/3 full. After he buys 3 gallons of gas, it is 1/2 full. How many gallons can Deshaun's tank hold?

rusak2 [61]

Answer:7 gallons

Step-by-step explanation:

6 0

2 years ago