<span>If you deposit(P) $6,800 in a money-market account that pays an annual interest rate(r) of 5.7%. The interest is compounded quarterly(4). [ The money you have after 3 years(t) is: Using the compound interest formula A=P(1+r/n)^nt, where P=$6800, r=57%=.057,t=+3, n=4. A=$6,800(1+(0.057/4))^(3x4) =$6,800(1+0.01425)^12 =$6,800(1.01425)^12 =$6,800(1.18505961016) =$8,058.41. ]</span>
Answer:
D. between 5.4 cm and 6.5 cm
Step-by-step explanation:
The segment is about 6cm
and 6cm is between 5.4 and 6.5
Answer:
1232 yards or 3696 feet or 44352 inches or 0.7 of a mile
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
