What is the y-intercept jn this linear equoation ? y=-4X + 4

ABC with altitude \overline{BD}

just olya [345]

The length of $\overline{AC}$ is given by the relationship between the similar triangles

ΔABD and ΔBDC.

$\overline{AC}$ = 80

Reasons:

The given parameters are;

The altitude of triangle ΔABD = $\overline {BD}$

The hypotenuse of formed right triangle = $\overline {AC}$

The length of AD = 8

Length of BD = 24

Whereby ΔABD is a right triangle

We have;

ΔABD is similar to ΔBDC

Therefore, by similar triangle proportional sides relationship, we have;

$\displaystyle \frac{\overline{AD}}{\overline{BD}} = \mathbf{ \frac{\overline{BD}}{\overline{DC}}}$

Which gives;

$\overline{BD}^2$ = $\mathbf{\overline{DC} \times \overline{AD}}$

Therefore;

$\displaystyle \overline{DC} = \mathbf{\frac{\overline{BD}^2}{\overline {AD}}}$

$\displaystyle \overline{DC} = \frac{24^2}{8} = \mathbf{72}$

$\overline{AC} = \overline{DC} + \overline{AD}$

Which gives;

$\overline{AC} = 72 + 8 =\mathbf{ 80}$

Learn more about similar triangles here:

brainly.com/question/4618367

8 0

2 years ago

If y/z=4/7, then z/y=

topjm [15]

Answer:

z/y = 7/4

Step-by-step explanation:

In y/z = 4/7, the numerator and denominator correspond with each other

So, y =4 and z = 7

5 0

3 years ago

State the various transformations applied to the base function to obtain a graph of the functiong(x) = |x + 1| − 2.

Arlecino [84]

345 i love your mom and I love your hair

7 0

3 years ago

The perimeter of a rectangle is 140 feet. The length of the rectangle is 6 more than 2 times the width. What is the length of th

Alja [10]

The equations we get are
l = 6 + 2w (We get this from "The length of the rectangle is 6 more than 2 times the width.")
and
2l + 2w = 140 (We get this from the perimeter. Two times the length plus two times the width equals the perimeter of a quadrilateral.)

The first equation can be written as
l - 2w = 6

So now we have
2l + 2w = 140
l - 2w = 6
____________
Add the two equations.
We get 3l = 146

Divide by 3 on both sides.
l = 48 $\frac{2}{3}$

Your answer is 48 $\frac{2}{3}$ .

5 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

3 years ago