Answer:
see attached
Step-by-step explanation:
Each spot in the triangle is the sum of the two numbers immediately above. The middle number of row 2 will be 1+1 = 2. The two numbers in row 3 will be 1+2 = 3 and 2+1 = 3. It continues like this. The second number in each row is the row number. Each row is symmetrical about the center.
Given :
Polynomial ,
.
To Find :
Integration of f(x) .
Solution :
We know , integration of
is :

( Here , is C is a constant )
Now ,

Therefore , the integration is
.
Hence , this is the required solution .
The answer is 63 degrees.
Answer:
1. Rectangle
2. 376.8 cm
3. 379.94 square feet
4. –4 and 4
Step-by-step explanation:
A square is always a rectangle.
If a wheel has a radius of 15 cm, it would travel approximately 376.8 cm per 4 revolutions.
If the diameter of a circular garden is 22 feet, the approximate area of the garden is 379.94 square feet.
The solutions to the equation y2 – 1 = 15 is –4 and 4.
Answer:
see attached
Step-by-step explanation:
I find it convenient to let a graphing calculator draw the graph (attached).
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If you're drawing the graph by hand, there are a couple of strategies that can be useful.
The first equation is almost in slope-intercept form. Dividing it by 2 will put it in that form:
y = 2x -4
This tells you that the y-intercept, (0, -4) is a point on the graph, as is the point that is up 2 and right 1 from there: (1, -2). A line through those points completes the graph.
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The second equation is in standard form, so the x- and y-intercepts are easily found. One way to do that is to divide by the constant on the right to get ...
x/2 +y/3 = 1
The denominators of the x-term and the y-term are the x-intercept and the y-intercept, respectively. If that is too mind-bending, you can simply set x=0 to find the y-intercept:
0 +2y = 6
y = 6/2 = 3
and set y=0 to find the x-intercept
3x +0 = 6
x = 6/3 = 2
Plot the intercepts and draw the line through them for the graph of this equation.
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Here, we have suggested graphing strategies that don't involve a lot of manipulation of the equations. The idea is to get there as quickly as possible with a minimum of mistakes.