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AysviL [449]
3 years ago
11

Find the area of the trapezoid to the nearest tenth.

Mathematics
1 answer:
marusya05 [52]3 years ago
3 0
You have not provided a diagram, therefore, I cannot provide you with the exact solution.
However, I will try to help you with the procedures on how to get the area of trapezoid and you can apply on the diagram you have.

Now, area of trapezoid can be calculated using the following rule:
area of trapezoid = \frac{b1 + b2}{2} * h

where:
b1 is the length of the first base
b2 is the length of the second base
h is the height of the trapezoid
The bases are the two parallel sides in the trapezoid

To better illustrate this, consider the attached diagram.
We have:
b1 = 5 m
b2 = 8 m
h is the perpendicular height = 4 m
Area = \frac{5+8}{2} *4 = 26 m²

Hope this helps :)

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Quinton bought x number of shares for p dollars and paid a 0.5% commission. He sold the stock for y dollars and paid a flat fee
Ksju [112]

Answer:

y-(0.05xp+7)

Step-by-step explanation:-

As per the statement:

Quinton bought x number of shares for p dollars and paid a 0.5% commission

⇒0.05xp

It is also given that: He sold the stock for y dollars and paid a flat fee of $7.

⇒y-7

then;

Net proceeds is given as:

y-7-0.05xp = y-(0.05xp+7)

Therefore, Quinton's net proceeds algebraically is y-(0.05xp+7)

4 0
3 years ago
Use the distributive property to simplify the following expression: -3(-x - 3y)
alexandr402 [8]

Step-by-step explanation:

-3(-x -3y) = 3( x +3y) = 3x+9y

7 0
3 years ago
Can someone help me please please please
marissa [1.9K]
Use the Pythagorean theorem a^{2} + b^{2} = c^{2} to find the missing side length of a right triangle 

In this case, after you plug in the given numbers your equation is 12^{2} +  y^{2}  =  20^{2}

Then, Just solve that equation for y.

144 +  y^{2} = 400

x^{2} = 256

\sqrt{} y^{2}  =  \sqrt{256}

y = 16

So the answer is B, 16 cm.

I hope this helps, please feel free to ask questions if you're still confused :)
7 0
4 years ago
How do you solve that?
Aleks [24]
Put it in the form 

ax^2 + bx + c = 0 

use the quadratic formula

x =  [ -b + sqrt( b^2 - 4 ac )  ] / 2a


x =  [ -b - sqrt( b^2 - 4 ac )  ] / 2a

7v^2 - 7v - 22 = 0

a = 7 
b = -7
c = -22

v = [  7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7  = 2.34

v = [  7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7  = -1.34


7 0
3 years ago
Read 2 more answers
Plz help me with these two questions I have no idea how to do this
viktelen [127]
(7-3+4^3/2) / (9-5)
7-3+64/2) / 4
(7-3 + 32) / 4
(4 + 32) / 4
36/4 = 9

48 + 72
24(2 + 3)

8 0
4 years ago
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