Find the area of the trapezoid to the nearest tenth.
1 answer:
You have not provided a diagram, therefore, I cannot provide you with the exact solution.
However, I will try to help you with the procedures on how to get the area of trapezoid and you can apply on the diagram you have.
Now, area of trapezoid can be calculated using the following rule:
area of trapezoid =
where:
b1 is the length of the first base
b2 is the length of the second base
h is the height of the trapezoid
The bases are the two parallel sides in the trapezoid
To better illustrate this, consider the attached diagram.
We have:
b1 = 5 m
b2 = 8 m
h is the perpendicular height = 4 m
Area =
= 26 m²
Hope this helps :)
However, I will try to help you with the procedures on how to get the area of trapezoid and you can apply on the diagram you have.
Now, area of trapezoid can be calculated using the following rule:
area of trapezoid =
where:
b1 is the length of the first base
b2 is the length of the second base
h is the height of the trapezoid
The bases are the two parallel sides in the trapezoid
To better illustrate this, consider the attached diagram.
We have:
b1 = 5 m
b2 = 8 m
h is the perpendicular height = 4 m
Area =
Hope this helps :)
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Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180
Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°