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Dmitry [639]
3 years ago
10

Determine whether each graph represents a function

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0
It is the graph in the middle because x can only have one y.
Hope that this helps :)
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Please help asap oiuytyghjkjhugytfhjkl
Alika [10]

Answer:

112

Step-by-step explanation:

correct me if im wrong.

I got this from doing 30 percent out of 160

160×0.30

160-48=112

7 0
3 years ago
Read 2 more answers
Find an equation of the line through the given pair of points. (-7,-5) and (-1,-9) The equation of the line is (Simplify your an
Phantasy [73]

Answer:

The equation of the line is y = -2/3x - 29/3

Step-by-step explanation:

The slope of these points (-7,-5) and (-1,-9) is m = -2/3

Once you plug that into the y = mx + b equation, you can see that the y-intercept is -29/3.

Put all of that into the y = mx + b equation and you'll get -->  y = -2/3x - 29/3

7 0
3 years ago
Y=x+5 y = x + 5 Find four points contained in the inverse. Express your values as an integer or simplified fraction.
Karolina [17]

Answer: (0,-5), (5, 0), (10, 5) and (15,10).

Step-by-step explanation:

Given equation: y = x + 5

To find its inverse we will find the value of x .

Subtract 5 from both sides

x=y-5

Switch y to x, we get

y= x-5, which is the inverse function.

At x=0,

y=-5

At x= 5,

y=0

At x= 10 ,

y=5

At x= 15,

y= 10

Hence, the four points contained in the inverse: (0,-5), (5, 0), (10, 5) and (15,10).

7 0
3 years ago
How do you solve y=5/8b + 10 for b
joja [24]

Answer:

b = \frac{8y-80}{5}

Step-by-step explanation:

Given

y = \frac{5}{8} b + 10

Multiply through by 8 to clear the fraction

8y = 5b + 80 ( subtract 80 from both sides )

8y - 80 = 5b ( divide both sides by 5 )

\frac{8y-80}{5} = b

5 0
4 years ago
What is the sum of 2 / 3x^2 +12x and 8 / c. Need steps
Marta_Voda [28]

Answer:

\frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c} [\tex]Step-by-step explanation:We need to find sum of 2 / 3x^2 +12x and 8 / cSo, solving:[tex](\frac{2}{3x^2} + 12 x ) +\frac{8}{c}

Taking LCM of 3x^2 and 1 i.e. 3x^2

=(\frac{2 + 12 x(3x^2)}{3x^2} ) +\frac{8}{c}\\=(\frac{2 + 36x^3}{3x^2} ) +\frac{8}{c}\\=\frac{2 + 36x^3}{3x^2} +\frac{8}{c}\\LCM \,\, 36x^2 c\\=\frac{(2 + 36x^3)c + 8(3x^2)}{3x^2c}\\=\frac{2c + 36x^3c + 24x^2}{3x^2c}\\= \frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c}

5 0
4 years ago
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