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Svetllana [295]
3 years ago
15

The power g2 is equivalent to 81. What is the value of g-2?

Mathematics
2 answers:
Serggg [28]3 years ago
8 0

Answer:

7

Step-by-step explanation:

g^2 =81

so, g=9

g-2=9-2=7

dalvyx [7]3 years ago
3 0

Answer: 1/81

Step-by-step explanation:

just took the test

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Solve 6n + 10 < 4n + 16
BartSMP [9]

Answer:

n < 3

Step-by-step explanation:

6n + 10 < 4n + 16

( Minus 4n from both sides to isolate + 16 )

2n + 10 < 16

( Minus 10 from both sides to isolate 2n )

2n < 6

( Divide both sides by 2 to isolate n )

n < 3

3 0
3 years ago
Read 2 more answers
The width and length of a rectangle (in feet)are consecutive odd integers. If the length is increased by 5 feet, the area of the
Tresset [83]
Original:
<span>The width and length of a rectangle are consecutive odd integers
</span>so W = x and L = x + 2

<span>If the length is increased by 5 feet, then new L = x + 2 + 5 = x + 7
</span>
A = L x W
60 = (x + 7) x
60 = x^2 + 7x
x^2 + 7x - 60 = 0
(x - 5)(x + 12) = 0
x = 5 and x = -12

From here you have x = W = 5 ft and L = x + 2 = 5 + 2 = 7 feet

Area of original = 5 x 7 = 35

answer 
<span>the area of the original rectangle: </span>35 ft^2


4 0
3 years ago
Which of these triangles are definitely right triangles?<br><br> (No links)
marusya05 [52]

Answer:

1: A

2: D

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5 0
3 years ago
A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet
Mariana [72]

The distance d is 9 ft and the height is 12ft.

<h3>How to find the distance and the height?</h3>

Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.

The height is one cathetus and the distance is the other catheti.

Let's define:

  • h = height
  • d = distance.
  • hypotenuse = 15ft

We know that the height of the tower is 3 ft larger than the distance, then:

h = d + 3ft

Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.

Then:

d^2 + (d + 3ft)^2 = (15ft)^2

Now we can solve this equation for d:

d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0

Then the solutions are:

d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}

We only take the positive solution:

d = (-3ft + 21ft)/2 = 9ft

And the height is 3 ft more than that, so:

h = 9ft + 3ft = 12ft

The distance d is 9 ft and the height is 12ft.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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2 years ago
T' is (6, 6) what is the scale factor of the dilation
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Is this all the information that you have 
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