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Ivenika [448]
3 years ago
14

Y = |x| a function true or false

Mathematics
2 answers:
Olin [163]3 years ago
7 0

Answer:

Yes Omobolaji see my other answer on you question for the explanation.

Step-by-step explanation:

Alla [95]3 years ago
6 0
<h2>Answer: <u>True</u></h2><h2>I hope this works </h2><h2>And Subscribe please</h2><h3><em>DeadlyGamerBeast_3000</em></h3>

Step-by-step explanation:

You might be interested in
What mix number is equivalent to 13/6
-BARSIC- [3]

Answer:

2 1/6

Step-by-step explanation:

4 0
3 years ago
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

(2x+3)=-4-\sqrt{5} or (2x+3)=-4+ \sqrt{5}

2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
3 years ago
Following the pattern in squaring a binomial, fill-in the missing term. I need fast, please ​
melisa1 [442]

Answer:

c

Step-by-step explanation:

im not completely sure

8 0
3 years ago
15y +5x- 7y+1x-3y i need help
vladimir2022 [97]

Answer:

simplify the expression: 6x+5y

Step-by-step explanation:

8 0
3 years ago
I don’t understand these question
Lemur [1.5K]
I believe question 3 is B and question 4 is B
5 0
3 years ago
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