Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
(0,0), (1,1)
Basically, any point that is shaded.
Simplify the following:
(k^3 k^7)/3 - 5
Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5
7 + 3 = 10:
k^10/3 - 5
Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3
k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
Answer:
(6 + 9) / 4
Step-by-step explanation: you have to add the costs of the appetizers and the main dish ( 6 + 9 ). then you have to divide the sum by 4 since there are 4 people in total ( /4 ).
F(y) = y + y^2 - 3
f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1
f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9
f(0) = 0 + 0^2 - 3
f(0) = -3
f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3
f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17
