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Dima020 [189]
3 years ago
10

The measure of Angle E, the angle of elevation from point A to point B, is left-parenthesis 3 x plus 1 right parenthesis-degrees

. The measure of Angle D, the angle of depression from point B to point A, is 2 left-parenthesis x plus 8 right parenthesis-degrees. Find the measure of each angle.
A. measure of angle E equals 22 degrees comma measure of angle D equals 30 degrees
B. measure of angle E equals 15 degrees comma measure of angle D equals 15 degrees
C. measure of angle E equals 46 degrees comma measure of angle D equals 46 degrees
D. measure of angle E equals 52 degrees comma measure of angle D equals 50 degrees
Mathematics
1 answer:
Orlov [11]3 years ago
6 0
Angle E and D are 46* C
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Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

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vekshin1

Answer:

There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the solution has an intersection with an infinite number of solutions.

Step-by-step explanation:

Its right on edg

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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