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lukranit [14]
4 years ago
5

Please help ♡♡♡♡♡♡♡♡​

Mathematics
2 answers:
hichkok12 [17]4 years ago
8 0
I hope the persons answer helps you!
Nina [5.8K]4 years ago
6 0
Your answer would be 2000
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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

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\cos P=\dfrac{490000+384400-705600}{868000}

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On further simplification, we get

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P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

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