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3 years ago

Someone help asap!!! Will give brainlist :)

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Answer:

$a) \: constant \: of \: proportionality \: (k) \\ = \frac{90}{2} \\ = 45 \\ \\ b) \: \frac{distance}{time} = k \\ \therefore \: \frac{d}{t} = k \\ \\ c) \: \frac{d}{t} = k \\ \\ \therefore \: d = tk$

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Part of a tiling design is shown. The center is a regular hexagon. A square is on each side of the hexagon, and an equilateral t

VMariaS [17]

1,119.6 in. the answer is c my diddle.

Find the area of the hexagon which is 259.81

Find the area of the squares which is (6)100

Find the area of the triangles which was (6)43.3

259.81 + 600 + 259.8

519.6 + 600 = 1119.6

8 0

3 years ago

a grocery store sells snacks by weight .a six ounce bag of mixed nuts costs $3.60 . predict the cost of two ounce bag

erastova [34]

First you have to find out how much one cost.
In order to do that you have to divide 3.60/6. You would get 6. That is how much one cost. Then you have to multiply 6*2 and you would 12. So the answer is $12. I hope this helps

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3 years ago

Simplify the following expressions ( combine like-terms )

galina1969 [7]

Answer:

Step-by-step explanation:

Step 1: Write equation

x + 2x + 3x

Step 2: Combine like terms

3x + 3x

5 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

You and a friend are running on treadmills. you run 0.5 mile every 3 minutes and your friend runs 2 miles every 14 minutes. you

Natali5045456 [20]

I run 1 mile every 6 minutes.
My friend runs 1 mile every 7 minutes.
Lowest Common Multiple: LCM ( 6, 7 ) = 42 minutes.
Me : 42 : 6 = 7 miles
My friend : 42 : 7 = 6 miles.

4 0

2 years ago

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