D.dilation changes the size is your answer. Hope this helps!
So... hmmm if you check the first picture below, for 2)
we could use the proportions of those small, medium and large similar triangles like
now.. for 3) will be the second picture below
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Greetings!</h2>
Answer:
3⋅(5⋅x)
5⋅(x⋅3)
15x
Step-by-step explanation:
As the values are inside the brackets, it does not matter what side the (x3) is on, so 3⋅(5⋅x) is equivalent.
Multiplying the contents of the brackets in the third one (x * 3) by 5 gives the same value as 3 * (x * 5) so 5⋅(x⋅3) is also equivalent.
On multiplying the brackets out:
5 * x = 5x
5x * 3 = 15x
So 15x is also equivalent.
<h2>Hope this helps!</h2>
You could roll a 6-sided die 3 times to simulate this. This is a good simulation because it has one side for each possible tool, and each roll is independent, just as selecting the tool with replacement would be.
Answer:
A. d ≤ –7 or d > 8.
Step-by-step explanation:
Given : 2d + 3 ≤ –11 or 3d – 9 > 15.
To find : What are the solutions of the compound inequality .
Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.
For 2d + 3 ≤ –11
On subtracting both sides by 3
2d ≤ –11 - 3 .
2d ≤ –14.
On dividing both sides by 2 .
d ≤ –7.
For 3d – 9 > 15.
On adding both sides by 9.
3d > 15 + 9 .
3d > 24 .
On dividing both sides by 3 .
d > 8 .
So, A. d ≤ –7 or d > 8.
Therefore, A. d ≤ –7 or d > 8.
