Answer:
31.925 ft
Step-by-step explanation:
A diagram is needed to visualize Dylan's movement to Alex see below
thus (-22.4)² + y² = 26²
y² = 26² - (22.4)² = 174.24
y = -√174.2 = - 13.2 ft note due south
closest point at intersection
3/11* ( x- 26) = -11/3 x * + 26
3/11 x - 78/11 = -11/3x + 26
3/11 x +11/3x = 26 + 78/11
130/33 x = 364/11
x = 364/11 * 33/130 = 8.4
then y = 3/11 * (x -26)
x = 8.4 substitute, gives y = 3/11 * (8.4 -26) = -4.8
distance from (8.4 , -4.8) to (0 , 26)
√[(0 -8.4)² + ( 26-(-4.8))² ] = √[( -8.4)² + ( 30.8)² ] = 31.925 ft
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
In this problem, it is essential to use the order of operations, or PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction). First, you solve 7-3=4. Then, you multiply 7 times 4, which is 28. Lastly, you add 28 to 156 which is 184. So your answer is B.
Answer:
8(x+4)x(x-7)
Step-by-step explanation:
hope this helps!
