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mestny [16]
3 years ago
7

In the figure, a∥b and m∠6 = 146°.

Mathematics
1 answer:
natka813 [3]3 years ago
3 0

Answer:146

Step-by-step explanation:

took a test :)

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Maybe Option 2? Not really sure just trying to help
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Alice and Bob both go to a party which starts at $5:00$. Each of them arrives at a random time between $5:00$ and $6:00$. What i
faltersainse [42]

The probability comes out to be 9/32.

Deducing Arrival Time Possibility

All the possible arrival times by Alice and Bob, in minutes after 5 PM, is constrained by the values of given values of x and y,

x = 0, y = 0, x = 60, y = 60.

Here, let the values of x represent how many minutes after 5 PM Alice arrives at the party.

Let the y values represent the time in minutes that Bob arrives at the party after 5 PM.

Calculating the Required Probability

The times that concern us, however, are obtained by the following probability function,

x + y ≤ 45.

And x = 0, y = 0, and x + y ≤ 45 define the constraints of this probability function. Thus the perimeter of such a graph will be given as,

(45² / 2) = 1012.5 square units

Since the total area of the various arrival times is 60 x 60, or 3600 square units, the probability that Alice and Bob will arrive together after 5 o'clock in the evening in less than 45 minutes is therefore = 1012.5 / 3600 = 9/32

Learn more about probability here:

brainly.com/question/11234923

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2 years ago
Solve the equation. 33= p - 6.71
Amiraneli [1.4K]
P=33+6.71
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GarryVolchara [31]

Answer:

height is 15

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therefore 15y = (-x^2) +(300/20)

Step-by-step explanation:

15 = -x^2 +(300/20)

is the same as;

15 = (300/20) - (x^2)

we just add y to 15 and that can represent a division for x

y = L

Where area cm^2 can be shown as 300 as 15 x 20 = 300

when we divide by length we get the height as asked in the question.

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