All categories

2 years ago

Evaluate the expression 7x^2y when x = 3 and y + 4 six grade math

Mathematics

1 answer:

Rom4ik [11]2 years ago

7 0

Answer:

21^8

Step-by-step explanation:

YUUUUPPPPPP

You might be interested in

What is the complex number z=−3+3√3i represented in polar form?<br><br><br> z=____cis(____)

maks197457 [2]

Answer:

Step-by-step explanation:

The general form of a complex number z = x+iy

If x = rcos $\theta$ and y = rsin $\theta$

where r is the modulus of the complex number and $\theta$ is the argument, z in polar form is represented as:

z = rcos $\theta$ + rsin $\theta$

z = r(cos $\theta$ + isin $\theta$ )

z = rcis $\theta$

Given the complex number z=−3+3√3i

r = $\sqrt{x^{2}+y^{2} }$

$r = \sqrt{(-3)^{2}+(3\sqrt{3})^{2} } \\r = \sqrt{9+27} \\r = \sqrt{36}\\ r = 6$

$argument\\\theta = arctan \frac{y}{x} \\\theta = arctan \frac{3\sqrt{3} }{-3} \\\theta = arctan {-\sqrt{3} } \\\theta = -60 \deg$

since the argument is negative and tan is negative in the 2nd and 4th quadrant,

In the second quadrant, theta = 180- 60 = 120°

On substituting r and theta, the complex number in polar form is expressed as 6cis120°

3 0

3 years ago

A bottle of water 2/3 full. You drink 3/4 of the water. Use a model to find the portion of the bottle of water that you drink .

Zanzabum

You drunk 1/1 of the bottle of water

6 0

2 years ago

Read 2 more answers

PLSSSSSSSSSSSSSSSSS HELP ME PLSSSSSSSSSSSSSSSSSSSSSSS

sp2606 [1]

Answer:

E. None of the above

Step-by-step explanation:

We know that 1/8 is the same as 1÷8 Then using Long Division for divided by 8 gives us 0.125

3 0

2 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum: