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Hitman42 [59]
3 years ago
10

Can someone help me pls

Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

C. 1/3x + 5

Step-by-step explanation:

Plugging in the values for x, we get:

y = 1/3(0) + 5 = 5

y = 1/3(6) + 5 = 7

y = 1/3(12) + 5 = 9

y = 1/3(15) + 5 = 10

I almost broke my neck trying to read this problem. :(

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Michelle is rolling two six-sided dice, numbered one through six. What is the probability that the sum of her rolls is 4? A. B.
Bad White [126]

Answer:

<h3>The probability that the sum of Michelle's rolls is 4 is 0.083 </h3><h3>∴ P(A)=0.083  </h3>

Step-by-step explanation:

Given that Michelle is rolling two six-sided dice, numbered one through six.

<h3>To find the probability that the sum of her rolls is 4:</h3>

s={\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\}

<h3>∴ n(s)=36</h3>

Let P(A) be the probability that the sum of her rolls is 4

Then the possible rolls with sums of 4 can be written as

A={\{(1,3),(2,2),(3,1)}\}

<h3>n(A)=3</h3>

The probability that the sum of her rolls is 4 is given by

P(A)=\frac{n(A)}{n(s)}

=\frac{3}{36}

=\frac{1}{12}

=0.083

<h3>∴ P(A)=0.083 </h3><h3>∴ the probability that the sum of Michelle's rolls is 4 is 0.083 </h3>
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3 years ago
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Simplifying

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Combine like terms: 2ab + 4ab = 6ab

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Solving

6ab = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '6'.

ab = 0

Simplifying

ab = 0

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Step-by-step explanation:

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