Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
Just divide 948.6 m^3 by 3.1 m and 5.1 m to get 60 m
Answer:
Bond Price= $1,070.24
Step-by-step explanation:
Giving the following information:
Cupon= $80
Number of periods= 10 years
Face value= $1,000
Interest rate= 7%
<u>To calculate the price of the bond, we need to use the following formula:</u>
Bond Price= cupon*{[1 - (1+i)^-n] / i} + [face value/(1+i)^n]
Bond Price= 80*{[1 - (1.07^-10)] / 0.07} + [1,000 / (1.07^10)]
Bond Price= 561.89 + 508.35
Bond Price= $1,070.24
Answer:
10.5
Step-by-step explanation:
4.50 ÷ 3 = 1.5
1.5 × 7 = 10.5
