Graph D(-7,-2), G(9,-2), K(9,10)

−4(m+6)=−8 plz answer

dangina [55]

Answer:Divide both sides by the numeric factor on the left side, then solve.

m

=

−

4

Step-by-step explanation:

5 0

2 years ago

Please help this needs to be turned in by tonight

KonstantinChe [14]

Answer:

big robux

Step-by-step explanation:

y=big robux big

5 0

2 years ago

Solve the system of equations y = 2x + 3 and 4x - 2y = -6 using a graphical method.

emmasim [6.3K]

Answer:

-1

Step-by-step explanation:

You are asked to solve this set by substitution. Note that the first equation defines

the value of y in terms of x. Therefore, you can use the right side of this equation

(2x + 3) as a substitution for y in the second equation. When you substitute 2x +3 for y

in the second equation, the result is:

.

2x + 3 = 4x + 7

.

Let's set the goal of getting all the terms that contain x isolated on the left side of

the equal sign and all the constants by themselves on the right side. Begin by getting rid

of the +3 on the left side by subtracting 3 from the left side. But if you subtract

3 from the left side you must also subtract 3 from the right side. These subtractions

result in the following sequence:

.

2x + 3 - 3 = 4x + 7 - 3

.

Combining numbers on the left side and on the right side simplifies the equation to:

.

2x = 4x + 4

.

Now, in a similar fashion, let's get rid of the 4x on the right side by subtracting

4x from the right side. When we do this subtraction, to keep the equation in balance

we must also subtract 4x from the left side. This results in:

.

2x - 4x = 4x - 4x + 4

.

On both sides of the equation combine terms containing x to get:

.

-2x = 4

.

Finally, solve for x by dividing both sides of the equation by -2 because -2 is the multiplier

of x. This results in:

.

x = 4/-2 = -2

.

So now that we know x = -2, we can return to either one of the original equations

in the equation set and substitute -2 for x. Then we can solve for y. Let's return

to the first equation and substitute -2 for x. This begins with:

.

y = 2x + 3

.

Then substituting -2 for x gives:

.

y = 2*(-2) + 3 = -4 + 3 = -1

7 0

2 years ago

A company logo is made up of a square and three identical triangles.

IgorLugansk [536]

Answer:

$the \: area \: of \: the \: logo \: is \: {91cm}^{2}$

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

$a = {a}^{2}$

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

$asquare = {7}^{2} \\ asquare = {49cm}^{2}$

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

$a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}$

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

$atriangles = 3a \\ atriangles = {42cm}^{2}$

Now that the area of all shape are calculated, you have to add them to determine the area of the logo:

$alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo = {91cm}^{2}$

4 0

3 years ago

Two cities are 210 km apart. A train traveled this distance in 4 2/3 hours and then made the return trip at a speed of 50 2/5 km

AveGali [126]

$4 \frac{2}{3}= \frac{14}{3}$

So, $\frac{210km}{ \frac{14}{3}hr }= 45km/h$

$50 \frac{2}{5} = \frac{252}{5}$

So, $\frac{252}{5}/45= 1.12$ times greater on the return trip.

7 0

3 years ago