Graph D(-7,-2), G(9,-2), K(9,10)
1 answer:
You might be interested in
The Poisson probability distribution function is
where
μ = mean number of successes
x = actual or expected number of successes
Given:
μ = 13
x = 5
Therefore the probability that x=5 is
P(x = 5) = (e⁻¹³*13⁵)/5!
= 0.8392/120
= 0.006994
= 0.0070 (to 4 dec. places)
Answer: 0.0070 (to 4 decimal places)
It is interesting to observe P(x) as x varies, as in the graph shown below.
where
μ = mean number of successes
x = actual or expected number of successes
Given:
μ = 13
x = 5
Therefore the probability that x=5 is
P(x = 5) = (e⁻¹³*13⁵)/5!
= 0.8392/120
= 0.006994
= 0.0070 (to 4 dec. places)
Answer: 0.0070 (to 4 decimal places)
It is interesting to observe P(x) as x varies, as in the graph shown below.