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Stolb23 [73]
3 years ago
15

O A PQR is reflected over the x-axis. What are the coordinates of O'?

Mathematics
2 answers:
lana66690 [7]3 years ago
8 0

Answer: 8, -2

Step-by-step explanation: When reflecting over the x axis, change the y.

topjm [15]3 years ago
7 0

Answer:

(8,-2)

Step-by-step explanation:

When reflecting something across the X axis the y axis coordinate is the one that will change to put the position further up or down.  In this case we are moving it down to the same amount below the axis that it is now above it.  That means that since it is currently 2 above the X axis it would then be 2 below the X axis making it at -2 so the coordinates would be (8,-2)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

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For every watch that Sarah sells, she earns $4. She gets an additional bonus of $50 for every 25 watches she sells. Last month,
kotegsom [21]

Answer:

89

Step-by-step explanation:

25 watches equals a $50 bonus + 25 * 4

25*4=100

100+50=150

150 can go into 506 three times with a remainder of 56.

since it fits three times that is 75 watches

now divided the remainder by 4 and add this to 75.

56/4=14

75+14=89

89 watches

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!
Sonbull [250]
2x^2 - 7x - 6 = 0

x1 = \frac{- b  +  \sqrt{ {b}^{2} - 4ac }}{2a}
x2 = \frac{- b   -   \sqrt{ {b}^{2} - 4ac }}{2a}
where a=2
where b=-7
where c=-6

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6 0
2 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
What scale factor was applied to the first rectangle to get the result image?
sleet_krkn [62]
I dont know what the images are but scale factor is <span>is a number which </span>scales<span>, or multiplies, some quantity. Technically it is the number you have to multiply on each side that will get you the sides on the smaller or larger rectangle!!!

I hope it helps!!!
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8 0
2 years ago
Read 2 more answers
Solve for z w(-4+z)=Mz+17
bogdanovich [222]

Answer:

z = \frac{17+4w}{w-M}

Step-by-step explanation:

6 0
3 years ago
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