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3 years ago

Which expression represents the difference (6b+9) – (7b — 4)?

Mathematics

1 answer:

Kazeer [188]3 years ago

7 0

Answer:

there arent any options but this is what i got

− b + 13

Step-by-step explanation:

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How do u simplify this: sqrt =square root<br> 2sqrt462cd^2 * sqrt7c^5d^2

Sveta_85 [38]

Answer: The simplified version of this is 14d²c³√66

Step-by-step explanation:

6 0

2 years ago

Stretch your thinking, solve the story problem. Draw comparison bars. There were 11 hikers here yesterday. There are 4 hikers he

Kryger [21]

11-4=7 your welcome

6 0

2 years ago

2sin^(-2490)+tan 1410

givi [52]

2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6

Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)

7 0

3 years ago

HELP ME pls

Andreas93 [3]

Answer:

34 and 30

Step-by-step explanation:

8 times 3 = 34

and 34-4=30

divide 8 by 2 and you'll get 4

so, 34-4=30

4 0

3 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

2 years ago