Answer:
Step-by-step explanation:
The Fundamental Theorem of Calculus states that:
![\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt \right] = f(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20%5Cint_a%5Ex%20f%28t%29%5C%2C%20dt%20%20%5Cright%5D%20%3D%20f%28x%29)
Where <em>a</em> is some constant.
We can let:
By substitution:
Taking the derivative of both sides results in:
![\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20g%27%28s%29%20%3D%20%5Cfrac%7Bd%7D%7Bds%7D%5Cleft%5B%20%5Cint_6%5Es%20g%28t%29%5C%2C%20dt%5Cright%5D)
Hence, by the Fundamental Theorem:
200*(107%)^x
x is the number of quarters that passed.
each year has 4 quarters, so 12 yaers would have: 12*4 = 48 quarters
200*(107%)^48 = 5146
23*10*8=1840
1840 cubic units
Answer:
5
Step-by-step explanation:
To find B and C prime, you must multiply them by .25, or 1/4.
B' =
(-2 x .25),(1 x .25)
I did mine in fraction form, because it will prove to be more useful in future mathematics.
B' = (1/2 , 1/4)
Repeat the process with C.
C' =
(14 x .25),(17 x .25)
C' =
(7/2 , 17/4)
You only need to focus on B and C because you are finding the length of B'C'.
The formula for distance is the square root of x to the sub of 2 minus x to the sub of 1 squared minus y to the sub of 2 minus y to the sub of 1 square.
x2 - x1 = 7/2 - 1/2 = 6/2 = 3 squared = 9
y2 - y1 = 17/4 - 1/4 = 16/4 = 4 squared = 16
16 + 9 = 25
Square root of 25 is 5.
Therefore, the distance is 5.
