Assuming that the 30 is term #1 ..... The 'n'th term of the series is. T(n) = 33 - 3n or 3 (11 - n).
Answer:
0.1384
Step-by-step explanation:
Using binomial probability:
P = nCr p^r q^(n-r)
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1-p).
Given n = 25, r = 4, p = 0.10, and q = 0.90:
P = ₂₅C₄ (0.10)⁴ (0.90)²⁵⁻⁴
P = 12650 (0.10)⁴ (0.90)²¹
P = 0.1384
Answer:
x= 12 units.
Step-by-step explanation:
To solve this equation, we can find each half of the base using the Pythagorean theorem. We will use 'x' as denoting each HALF of the base:
45= 3²+x²
Subtracting from both sides will give us:
36= x²
x=6.
However, the base in this problem is '2x' because 'x' is HALF of the base.
2(6)= 12 units.
X = 0, y = 4, z = -3
You can solve this by using the two equations with the z to create a fourth equation. Get the z's to equal each other my multiplying the whole equation by factors that would do so. Then subtract them from each other to get it to cancel out. Then you can use that equation along with the middle equation to solve for either x or y in the same way. Once you have one answer, you can use the middle equation to find the second one and any equation to find z.
Recall that given the equation of the second degree (or quadratic)
ax ^ 2 + bx + c
Its solutions are:
x = (- b +/- root (b ^ 2-4ac)) / 2a
discriminating:
d = root (b ^ 2-4ac)
If d> 0, then the two roots are real (the radicand of the formula is positive).
If d = 0, then the root of the formula is 0 and, therefore, there is only one solution that is real and of multiplicity 2 (it is a double root).
If d <0, then the two roots are complex and, in addition, one is the conjugate of the other. That is, if one solution is x1 = a + bi, then the other solution is x2 = a-bi (we are assuming that a, b, c are real).
One solution:
A cut point with the x axis
Two solutions:
Two cutting points with the x axis.
Complex solutions:
Does not cut to the x axis
