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3 years ago

Which statements describe the Mercalli scale? Check all that apply.

Physics

1 answer:

konstantin123 [22]3 years ago

3 0

<h3><u>Full question:</u></h3>

Which statements describe the Mercalli scale? Check all that apply.

A. This scale measures seismic waves based on their size.

B. This scale rates an earthquake according to how much damage it causes.

C.This scale produces a single rating for earthquakes that reach the surface.

D. This scale uses Roman numerals to rank the damage caused by an earthquake.

E.This scale measures the magnitude of an earthquake based on the size of seismic waves.

<h3><u>Answer:</u></h3>

The Mercalli scale : This scale rates an earthquake according to how much damage it causes and This scale uses Roman numerals to rank the damage caused by an earthquake.

<h3><u>Explanation:</u></h3>

The Modified Mercalli scale is intended to illustrate the consequences of an earthquake, at a contracted station, on tangible characteristics, on modern fittings and human beings.

The Modified Mercalli Intensity value ascribed to a particular site subsequent an earthquake has an extra significant means of severity to the nonscientist than the magnitude because intensity assigns to the outcomes really encountered at that position. This scale is comprised of 12 growing levels of intensity, denoted by Roman numerals, arranging from gradual shaking to catastrophic impairment.

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One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor

Bess [88]

Answer:

a) The final velocity is 20 m/s when the large-mass object is the one moving initially.

b) The final velocity is 9.0 m/s when the small-mass object is the one moving initially.

Explanation:

The momentum of the system is calculated as the sum of the momenta of each object. Each momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

Then, the momentum of the system is the following:

m1 · v1 + m2 · v2 = (m1 + m2) · v

Where:

m1 = mass of the bigger object.

v1 = velocity of the bigger object.

m2 = mass of the smaller object.

v2 = velocity of the smaller object.

v = final velocity of the two objects after the collision.

Solving the equation for the final velocity:

(m1 · v1 + m2 · v2)/ (m1 + m2) = v

a) Let´s calculate the final velocity when the bigger object is moving:

(7.1 kg · 29 m/s + 3.2 kg · 0)/(7.1 kg + 3.2 kg) = v

b) When the smaller object is moving:

(7.1 kg · 0 m/s + 3.2 kg · 29 m/s) / (7.1 kg + 3.2 kg) = v

7 0

4 years ago

Alcohol of mass 33.2g and density 0.79kg/m³ or 790kg/m³ is mixed with water of 9g. What is the density of the resulting mixture?

KATRIN_1 [288]

Answer:

0.83 g/cm³

Explanation:

The volume of the alcohol is ...

(33.2 g)/(0.79 g/cm³) ≈ 42.0253 cm³

The density of water is about 1 g/cm³, so the volume of 9 g of it is ...

(9 g)/(1 g/cm³) = 9 cm³

The total volume is ...

42.0253 cm³ +9 cm³ = 51.0253 cm³

The total mass is ...

33.2 g + 9 g = 42.4 g

So, the resulting density is ...

(42.4 g)/(51.0253 cm³) ≈ 0.83 g/cm³

The resulting mixture has a density of about 0.83 g/cm³.

_____

<em>Additional comment</em>

Alcohol dissolves in water, so the total volume will be slightly less than 51.0253 cm³. The attached curve shows the result of mixing ethanol and water.

The weight of a mole of ethanol is about 46 g, of water, about 18.02 g. Then the mole fraction of alcohol is ...

(33.2/46)/(33.2/46 +9/18.02) ≈ 0.59

The volume of the mix is then estimated to be (-1.05 cc/mol)(1.221 mol), or about 1.28 cm³ less than the volume indicated above. That brings the density up to about 0.85 g/cm³.

We're not completely sure of the relevance of this calculation, since many of the applicable parameters are not specified. The point is that <em>the density of the mix will probably be slightly more than the value calculated above</em>. YMMV