Answer:
22.5 miles due North
38.7 miles due East
Explanation:
From the information given above, we infer :
Let there be a <u>vector <em>AB</em></u><em> </em>(indicating distance travelled) with <em><u>magnitude = 45 </u><u>mi</u></em><u> </u> and makes an angle of <em>30° with East axis</em> as well as an angle of <em>60° with North axis</em>.
<u>Displacement covered in North Direction </u><u>:</u>
AB Cos 60° = <em><u>22.5 miles due North </u></em>
<u>Displacement covered in East Direction</u> :
AB Cos 30° = <em><u>38.7 miles due East</u></em>
The basic relationship between voltage, resistance and current of an electrical device is given by Ohm's law:
where
V is the voltage
I is the current
R is the resistance
The hot plate in our problem is connected to a source of V=120 V and it has a resistance of
, therefore we can rearrange the previous equation to calculate the current through the device:
Chameleon tongue reaches 23 cm.
Train's final speed is 32 m/s.
The distance the tongue travels is divided into 2 phases.
1. The acceleration phase.
2. The coasting phase.
For the acceleration phase, the formula d = 0.5AT^2 determines how far the tongue travels while accelerating. The during the coasting phase, the tongue continues onward without changing its velocity, so it's formula is d = VT. The peak velocity of the tongue will be reached after 20 ms. So let's calculate it.
d = 0.5AT^2
d = 0.5*290 m/s^2 * (0.020 s)^2
d = 145 m/s^2 * 0.0004 s^2
d = 0.058 m
Now to handle coasting
d = 0.058 m + 0.030 s * 290 m/s^2 * 0.20 s
d = 0.058 m + 0.174 m
d = 0.232 m
Rounding to 2 significant digits gives 0.23 meters, or 23 cm.
For the train, we need to determine the acceleration. We know the velocity changed from 5.0 m/s to 14.0 m/s over a period of 8.0 seconds. So the acceleration is:
(14.0 m/s - 5.0 m/s)/8.0 s = (9.0 m/s)/8.0 s = 1.125 m/s^2
At the edge of town, the train is traveling at 14 m/s and accelerates at 1.125 m/s^2 for 16 seconds, so:
14 m/s + 1.125 m/s^2 * 16 s = 14 m/s + 18 m/s = 32 m/s
So the final speed of the train is 32 m/s
Answer:
The average current will be "17.69 nA".
Explanation:
The given values are:
Charge,
q = 9.2 pC
Time,
t = 0.52ms
The equivalent circuit of the cell surface is provided by:
⇒
Or,
⇒
On substituting the given values, we get
⇒
⇒
⇒
Answer:
Honestly I cant understand that so please explain it someone
Explanation: