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3 years ago

Which of the following objects is in static equilibrium?

Physics

1 answer:

DedPeter [7]3 years ago

6 0

Answer:

b- a bicycle sitting on the ground

Explanation:

'Static' means it's not moving.

So, only the answer listed as "a bicycle sitting on the ground" corresponds to that condition.

All others possible answers describe something that is moving (an apple falling, a motorcycle accelerating, a car moving at a constant speed). Even if they are going at a constant speed, they are moving, so not static.

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11B5 + 4He2 14 N7 + ____

Crazy boy [7]

Answer:

EN PAISES TERCERMUNDITASS COMO EL MIO NO ENSEÑAN ESTAS COSAS ._.

Explanation:

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2 years ago

Why is it hard to respond with action at times?

solong [7]

Yes it can be very hard

3 0

3 years ago

Read 2 more answers

an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a

finlep [7]

Answer:

force; distance; energy.

Explanation:

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

$Impulse = force * time$

An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.

Mathematically, work done is given by the formula;

$Work done = force * distance$

4 0

3 years ago

Physics Question: Determine the work that is being done by tension in pulling the box 193.0 cm along the table. Also determine t

lozanna [386]

1) The work done by tension is 12.0 J

2) The final speed of the box is 1.57 m/s

Explanation:

The work done by a force on an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

F = 6.2 N is the force applied (the tension in the string)

d = 193.0 cm = 1.93 m is the displacement

$\theta=0$ assuming that the string is horizontal

Substituting, we find the work done by the tension:

$W=(6.2)(1.93)(cos 0)=12.0 J$

In order to determine the final speed of the box, we need to determine its acceleration first.

Beside the tension, acting forward, the other force acting horizontally on the box is the force of friction, whose magnitude is

$F_f = \mu mg$

where

$\mu=0.16$ is the coefficient of friction

m = 2.8 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F_f = (0.16)(2.8)(9.8)=4.4 N$

Therefore, the net force on the box is

$F=6.2 N - 4.4 N = 1.8 N$

And the acceleration can be found by using Newton's second law:

$F=ma$

where

F = 1.8 N is the net force

m = 2.8 kg is the mass of the box

a is the acceleration

Solving for a,

$a=\frac{F}{m}=\frac{1.8}{2.8}=0.64 m/s^2$

Now we can finally find the final speed using the suvat equation:

$v^2-u^2=2as$

where

v is the final speed

u = 0 is the initial speed

$a=0.64 m/s^2$ is the acceleration

s = 1.93 m is the displacement

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(0.64)(1.93)}=1.57 m/s$

Learn more about work:

brainly.com/question/6763771

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#LearnwithBrainly

3 0

3 years ago

What is the gravitational force between two 1 kg objects that are 1 m apart?

lapo4ka [179]

Answer:

$F=6.67\times 10^{-11}\ N$

Explanation:

Given that,

The masses of two objects, m₁ = m₂ = 1 kg

The distance between masses, d = 1 m

We need to find the gravitational force between two masses. The force is given by the relation as follows :

$F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N$

So, the force between two masses of 1 kg is $6.67\times 10^{-11}\ N$ .

3 0

3 years ago