First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Answer:
So the height is 12
Step-by-step explanation:
Let W be the width
Let W- 4 be the height
W2 +(W-4)2 = 400
So: W2 -4W-192 =0
One uses the quadratic solution:
W = (4 + (16 + 4*192).5)/2 = 16
Answer:
15 and 75
Step-by-step explanation:
complementary - add up to 90 degrees
x+5x=90 degrees
6x=90 degrees
x=90/6
x=15
15*5=75
Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
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