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klio [65]
3 years ago
12

Carl went to the store to buy items for his party.He bought two packs for plates for $3.24 and a pack of cups for $5.70. He also

bought a pack of forks for $6.17. If Carl paid with two $10 bills ,how much change did he get back
Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

3.24 + 5.70 + 6.17 = 15.11

20.00 - 15.11 = 5.11

He got 5.11$ of change back.

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Step-by-step explanation:

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José put $1,500 into a savings account. He earns 3% interest every year. How much simple interest will he earn at the end of 3 y
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He would have a total of: $1639.09

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Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

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3 years ago
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