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3 years ago

7

If your algorithm runs its critical section 1 + 2 + 3 + ... + (n-2) + (n-1) + n times, what is the asymptotic behavior of the al

gorithm?

1 answer:

Paraphin [41]3 years ago

4 0

If 1 and 2 becomes multiplayed gave 3 and 3+3=4 (4-2)+(4-1)= 2+3=4 and 4 is n.

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Find the Perimeters of the rectangle whale<br>degonal is 5cm and lenght is 4cm

amid [387]

Answer:

14

Step-by-step explanation:

First, we have to get the breadth value.

By the pythagoras theoreom,

Diagonal²=length² + breadth²

breadth = √( Diagonal²- length²)

breadth = √( 5² - 4²)

breadth = √9

breadth= 3

Perimeter of a rectangle = 2x ( length + breadth)

= 2 x ( 4 + 3)

= 2 x 7

= 14

3 0

3 years ago

Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.

madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

$\Rightarrow ^2C_1$

Total no of ways of choosing a marble from bag-I

$\Rightarrow ^{10}C_1$

No of ways of choosing a blue marble from bag-II

$\Rightarrow ^{10}C_1$

Total no of ways of choosing a marble from bag-II

$\Rightarrow ^{20}C_1$

The probability that he will pull out a blue marble from each bag is

$\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}$

$\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}$

3 0

3 years ago

The height of an object tossed upward with an initial velocity of 120 feet per second is given by the formula h = −16t2 + 120t,

AleksAgata [21]

Answer:

7.5 seconds

Step-by-step explanation:

$h = - 16 {t}^{2} + 120t \\ \because \: we \: have \: to \: find \: the \: time \: required \: \\ for \: the \: object \: to \: return to \: its \: \\ point \: of departure. \\ \therefore \: plug \: h = 0 \: in \: the \: given \: euation. \\ \therefore \: 0 = - 16 {t}^{2} + 120t \\ \therefore \:16 {t}^{2} - 120t = 0 \\ \therefore \:8t(2t - 15) = 0 \\ \therefore \:8t = 0 \: \: or \: \: (2t - 15) = 0 \\ \therefore \:t = \frac{0}{8} \: or \: t = \frac{15}{2} \\ \therefore \:t = 0 \: or \: t = 7.5 \\ \because \: t = 0 \: is \: not \: possible \\ \huge \purple{ \boxed{ \therefore \: t = 7.5 \: seconds}}$

Thus, the time required for the object to return to its point of departure is 7.5 seconds.

4 0

3 years ago

Answer the following answer this for me please I need help.

scoray [572]

Since the square root of 13 is something really weird (3.6055 something) and does not have a clear end or repeats, it is irrational. Solve for the number before assuming anything

5 0

3 years ago

Hilda adds 5 to a number, then multiplies the sum by negative 2. The result is 6. Write an equation to find the number, x.

adell [148]

The equation would be x+5*-2=6.

The result of that equation would be x=16

7 0

3 years ago

Read 2 more answers