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dimulka [17.4K]
2 years ago
13

Suzie made a mistake in the following problem. The mistake was made in Line ___. Only input the number of the first incorrect li

ne. Line 1 7(6) ÷ 5 + 42 Line 2 7(6) ÷ 5 + 16 Line 3 42 ÷ 5 + 16 Line 4 42 ÷ 21 Line 5 2
Mathematics
1 answer:
zalisa [80]2 years ago
3 0

Answer:

Mistake in Line 2

Step-by-step explanation:

Line 1  

7(6) ÷ 5 + 42  

Line 2  

7(6) ÷ 5 + 16  

Line 3  

42 ÷ 5 + 16  

Line 4  

42 ÷ 21  

Line 5  

2

To simplify any expression we use order of operation

Line 1 is 7(6) ÷ 5 + 42  

Order of operation is PEMDAS

First we start with parenthesis

so we multiply 7(6) in line 2

7*6- 42

So Line 2 is 42 ÷ 5 + 42  

Hence there is a mistake in Line 2

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Which Numbers are listed from least to greatest : A : 300, 0, - 200, - 250, or B : - 250, - 200, 0, 300 or C : 0, - 200, - 250,
Komok [63]
The answer is B. -250, -200, 0, 300
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Simplify these expressions<br> a) 13x+2y-10x-7y
joja [24]

\bold\green{Answer}:-

13x + 2y - 10x - 7y \\ 3x - 5y

<u>I </u><u>hope </u><u>it </u><u>helped </u><u>u </u>

7 0
2 years ago
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An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

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Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

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4 0
3 years ago
Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf
likoan [24]
<h3>2 Answers: Choice C and Choice D</h3>

==========================================================

Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

----------------

If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

----------------

Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

----------------

Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

------------------

Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

------------------

Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0
3 years ago
I'm so stuck plz help me!!!
elena-14-01-66 [18.8K]
Cd is equal to this: first calculate AB by sin30 which is radical 3 then by sin45 you know bc is radical 3 too then by fisaghures ( idk what you call it)
calculate bd at the end you just gotta do this: bd-bc



3 -   \sqrt{3}
7 0
3 years ago
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