Question

Sam has $440 in $20, $10, and $5 dollar bills. The number of twenties, tens and fives are consecutive integers in this order. How many bills does he have in all?

Answer 1

Answer: There are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

Step-by-step explanation:

Let the number of twenties be x

Let the number of tens be x+1

Let the number of fives be x+2

Amount from twenties will be given as

$20\times x=20x$

Amount from tens will be given as

$10\times (x+1)=10x+10$

Amount from fives will be given as

$5\times (x+2)=5x+10$

According to question,

$20x+10x+10+5x+10=440\\\\35x+20=440\\\\35x=440-20\\\\35x=420\\\\x=\frac{420}{35}\\\\x=12$

So, there are 12 bills for $20, 13 bills for $10 and 14 bills for $5.