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3 years ago

What is the radius of the circle whose equation is x2 + y2 = 8? 2 4 64

Mathematics

2 answers:

Naily [24]3 years ago

8 0

Answer:

The equation of circle of radius r whose centre is the origin (0, 0) ,

It is given by: $x^2+y^2 =r^2$ ......[1]

Given the equation: $x^2+y^2 =8$

To find the radius of the circle;

Compare the given equation with [1] we have;

$r^2 = 8$

Taking square root both sides we get;

$r = \sqrt{8} = 2\sqrt{2}$ units

Therefore, the radius of the circle is, $2\sqrt{2}$ units

umka2103 [35]3 years ago

6 0

It would be
$\sqrt{8}$
Or
$2\sqrt{2}$

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2 years ago

Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

• cos2x

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$

$\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}$

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

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1 year ago

Evaluate 4 - 2(a2 – b2)2 when a = 3 and b = 2.

Anton [14]

Answer:

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Step-by-step explanation:

4 - 2(a^2 – b^2)^2 =

= 4 - 2(3^2 – 2^2)^2

= 4 - 2(9 - 4)^2

= 4 - 2(5)^2

= 4 - 2(25)

= 4 - 50

= -46

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2 years ago

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