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Colt1911 [192]
3 years ago
14

A driver wants to gauge the fuel efficiency of

Mathematics
2 answers:
WITCHER [35]3 years ago
6 0

Answer: Y = -2X + 105

Step-by-step explanation: let speed = x and mpg = y

Using linear equation

Y = MX +c

M = dy/dt = (15 - 25)/( 40 - 45) =

-10/5 = -2

When y = 15 , x = 45

15 = -2(45) + c

15 = -90 + c

C = 105

The model linear equation will be

Y = -2X + 105

makkiz [27]3 years ago
6 0

Answer:

m = -2s + 105 for s > 30

Step-by-step explanation:

To get the gas mileage (m) as a function of average  speed (s) mph. If  m is for the fuel efficiency and s is for the average speed, it can be represented by the equation of a straight line.

(s₁, m₁) = (40, 25) and (s₂, m₂) = (45, 15)

The equation is given by:

\frac{m-m_1}{s-s_1} =\frac{m_2-m_1}{s_2-s_1}

Substituting values:

\frac{m-25}{s-40} =\frac{15-25}{45-40}

\frac{m-25}{s-40} =-2

m-25 =-2(s-40)\\m-25=-2s+80\\m = -2s+105

m = -2s + 105 for s > 30

m is in mpg and s is in mph

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