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crimeas [40]
3 years ago
8

Hallie bikes 1 5/8 km before lunch and 6 1/4 km after lunch. How much farther does Hallie bike after lunch than before lunch? Ex

press your answer as a mixed number in simplest form.
Mathematics
1 answer:
EleoNora [17]3 years ago
4 0

Answer:

4 \frac{5}{8} km

Step-by-step explanation:

To find how much farther Hallie biked after lunch compared to the amount she biked before lunch, we can subtract the amounts:

6 \frac{1}{4}-1\frac{5}{8}

However, we can only subtract fractions that have the same denominator, so we need to convert \frac{1}{4} to a fraction with a denominator of 8:

\frac{1}{4}=\frac{2}{8}

Now, we can't subtract 2 from 8, so we need to 'borrow' from the 6 to make the fraction larger:

6\frac{2}{8}=5\frac{10}{8}

Now subtract: 5\frac{10}{8}-1\frac{5}{8}=4\frac{5}{8}

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Answer:

=11600/3

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Step-by-step explanation:

dividing the mass with bricks with the three times of the lorry

8 0
3 years ago
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Nookie1986 [14]

Answer:

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Step-by-step explanation:

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3 years ago
Find the first three terms of the series represented by the formula 3(- 2)(n - 1).
enyata [817]

Answer:

0, - 6, - 12

Step-by-step explanation:

To find the first 3 terms, substitute n = 1, 2, 3 into the formula

a₁ = 3(- 2)(1 - 1) = 3 × - 2 × 0 = 0

a₂ = 3(- 2)(2 - 1) = 3 × - 2 × 1 = - 6

a₃ = 3(- 2)(3 - 1) = 3 × - 2 × 2 = - 12

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8 0
3 years ago
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NemiM [27]
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4 0
3 years ago
a man bought a motor at 400,000 Kenyan shillings in January 1999 it depreciated at a rate of 16% per annum if he value it six mo
Alexxx [7]

The value of the car is January 2003 is  $199,148.54.

<h3>What is the value of the car?</h3>

Depreciation is the rate of decline in the value of an asset with the passage of time.

The exponential equation that can be used to determine the value of the car is:

Value of the car = purchase value(1 - rate of decline)^time

400,000 x (1 - 0.16)^(2003 - 1999)

400,000 x (0.84^4) = $199,148.54

To learn more about depreciation, please check: brainly.com/question/15085226

#SPJ1

8 0
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