The magnitude of normal force that floor exerts on chair is 100.83N
<u>Explanation:</u>
Given:
Weight of chair, W = 75N
Applied force, F = 42N
Angle, θ = 38°
Normal force, n = ?
We know,
Vertical component of the force = F sinθ
= 42 X sin38°
= 42 X 0.615
= 25.83N
Total normal force acting on the chair = 75N + 25.83N
= 100.83N
Therefore, the magnitude of normal force that floor exerts on chair is 100.83N
River shore is located at distance
speed of the woman is given as
now the time taken by the woman to cover the distance is
for the same time interval the dog will run to and fro with speed 4.5 m/s
so the total distance moved by the dog is given by
<em>so the total distance that dog will move is 7200 m or 7.2 km</em>
Answer:
Explanation:
Assume the rod is horizontal
Sum vertical forces to zero
F - 8 - 4 - 2 - 3 = 0
F = 17 N
While this result answers precisely the question asked, it is not sufficient to guarantee equilibrium. We must also locate this force by summing moments to zero. Let's choose to sum about the left end.
8[9/2] + 4[1] + 2[6] + 3[4] - 17[x] = 0
x = 3.76470588...
the force must be supplied upward approximately 3.765 m from the left end
The rod does not actually have to be horizontal. Moment arms will all be proportionately reduced by tilting the bar from horizontal and the results will be identical. Assuming horizontal just reduces the calculation effort.
The answer I think is C -7.6 m/s
Answer:
carbon, hydrogen, nitrogen and oxygen