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4 years ago

How much power is used by a hair dryer if it does 40,000 J of work in 40 seconds?

Physics

1 answer:

bearhunter [10]4 years ago

6 0

Answer:

40000÷40=1000 joules is required to work in 40 seconds

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A plane is flying horizontally with speed 237 m/s at a height 1620m above the ground when a package is dropped for the plane. Th

Thepotemich [5.8K]

1. 0.5g*t^2 = 2010 m.

4.9t^2 = 2010.

t = 20.3 s. = Fall time.

D = Xo*t. = 193m/s * 20.3s = 3909 m.

2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.

3. Vo*t + 0.5g*t^2 = 2010 m.

58*t + 4.9*t^2 = 2010.

4.9t^2 + 58t - 2010 = 0.

Use Quadratic Formula.

t = 15.2 s. = Fall time.

D = 193m/s * 15.2s = 2934 m.

4 0

3 years ago

Sarah added sugar to her iced tea, but it is not dissolving very quickly. Which can Sarah do to make the sugar dissolve faster?

saw5 [17]

Heat the tea because the heat make the tea's particles move around more dissolving the sugar quicker

5 0

3 years ago

Read 2 more answers

URGENT PLEASE ANSWER: It takes about four minutes to bake a potato in a 1000 W microwave oven. How much energy is used?

mamaluj [8]

0.07 is the correct answer

6 0

3 years ago

Read 2 more answers

What average net force is required to accelerate a 9.5 g

Nesterboy [21]

Answer:

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

= 650² ÷ 2(0.85)

= 248,529.40 m/s²

But;

F = ma

= 0.0095 kg × 248,529.40 m/s²

= 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

6 0

3 years ago

Point A and B located at 4 meters and 9 meters from a source of the sound. If IA and IB are intensity at point A and point B, th

elena-14-01-66 [18.8K]

The intensity ratio at point A and B will be 81:16.

<u>Explanation:</u>

Sound waves are known to get faded with increase in the distance. This is because, the intensity of the sound is inversely proportional to the square of the distance of the source from the observer. So, if an observer is standing greater distance from the source of the sound, he/she will find difficulty in hearing the sound.

So, as the distance between the source and observer increases, the intensity of the sound wave decreases.

$I = \frac{1}{r^{2} }$

As here two points A and B are located at 4 m and 9 m distance from the source, then the intensity of sound at A and B will be inversely proportional to their respective square of the distance as shown below.

$I_{A} =\frac{1}{r_{A}^{2} } = \frac{1}{4 \times 4}=\frac{1}{16}$

Similarly,

$I_{B} =\frac{1}{r_{B}^{2} } = \frac{1}{9 \times 9}=\frac{1}{81}$

So, the ratio of intensity at point A and B will be

$\frac{I_{A} }{I_{B} } = \frac{81}{16} =81:16$

Thus, the intensity ratio at point A and B will be 81:16.

7 0

3 years ago