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Luda [366]
3 years ago
14

Find the measure of each angle of triangle abc, given ac=6, cb= 2 square roots of 3, and ab= 4 square roots of 3

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0
Note that 
(4sqrt3)^2 = (2sqrt3)^2 + 6^2     [ 48  =   12 + 36]  so the triangle is  a right angled one with hypotenuse AB 

So angle C = 90 degrees

sin A =   2 sqrt3 / 4 sqrt3 = 1.2  giving A = 30 degrees
and B = 90 - 30 = 60 degrees


A = 30, B = 60 and C = 90 degrees
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X + 2 – z; use x = 6, and z = 2​
grin007 [14]

Answer:

6

Step-by-step explanation:

  • x + 2 - z
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  • answer is 6
4 0
3 years ago
If m∠EBF = 6x + 4 and m∠CBF = 7x – 2, find m∠EBF.
olganol [36]

Answer:

78

Step-by-step

I hope it's helped

6 0
3 years ago
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Andy has 310 in his account. Each week w he withdraws 30 for his expences which expression could be used if he wanted to find ou
Butoxors [25]
310-30x=y
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3 0
3 years ago
Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals and finds that 48 rent their
Andreas93 [3]

Answer:

0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

0.192 + 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.233

Step-by-step explanation:

Information given

X= 48 number of people who rent their home

n= 250 represent the sample size

\hat p =\frac{48}{250}= 0.192 represent the proportion of people who rent their home

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=\pm 1.645

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

0.192 + 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.233

3 0
3 years ago
Find all angles, 0 ≤C<360 that satisfy the equation below, to the nearest tenth of a degree.
ludmilkaskok [199]

Move all the terms involving the sine to one side, and all the numbers to the other:

9\sin(c)-2=\sin(c)-7 \iff 8\sin(c) = -5\iff \sin(c)=-\dfrac{5}{8} \iff c = \arcsin\left(-\dfrac{5}{8}\right)\approx 321.3

7 0
3 years ago
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