Log4 + logX + log13 = 0
logX = -log13 - log4
logX = -1.716
x= 10^[-1.716]
x= 0.019 A
mult .13 with 134
add that to 134
then divide by 2 then that should be your answer
Answer:
6400
Step-by-step explanation:
she has $13.80 every hour because 842 divided by 40 plus 12 equals 61 so then and you cant round anymore.
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
