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ELEN [110]
3 years ago
9

When a fraction is reduced to lowest terms, the only factor the numerator and denominator have in common is

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer: A fraction is in lowest terms when the numerator and denominator have no common factor other than 1.

Step-by-step explanation:  The factors of 2 are 1 and 2. The factors of 4 are 1, 2, and 4. 2 and 4 share a common factor: 2.

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Use a formula to find the monthly payment on a home mortgage of $84,400 at 4.884% interest for 15 years.
leonid [27]
The applicable formula is
  A = P(r/12)/(1 -(1+r/12)^(-12n))
where P is the principal amount,
r is the annual interest rate (compounded monthly), and
n is the number of years.

Using the formula, we find
  A = 84,400*(0.04884/12)/(1 -(1+0.04884/12)^(-12*15))
  = 84,400*0.00407/(1 -1.00407^-180)
  = 343.508/0.518627
  ≈ 662.34

The monthly payment on a mortgage of $84,400 for 15 years at 4.884% will be
  $662.34
6 0
3 years ago
Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d
Stella [2.4K]

The answer is most likely A.

The integration interval [<em>a</em>, <em>b</em>] is split up into <em>n</em> subintervals of equal length (so each subinterval has width (<em>b</em> - <em>a</em>)/<em>n</em>, same as the coefficient of the sum of <em>y</em> terms) and approximated by the area of <em>n</em> rectangles with base (<em>b</em> - <em>a</em>)/<em>n</em> and height <em>y</em>.

<em>n</em> subintervals require <em>n</em> + 1 points, with

<em>x</em>₀ = <em>a</em>

<em>x</em>₁ = <em>a</em> + (<em>b</em> - <em>a</em>)/<em>n</em>

<em>x</em>₂ = <em>a</em> + 2(<em>b</em> - <em>a</em>)/<em>n</em>

and so on up to the last point <em>x</em> = <em>b</em>. The right endpoints are <em>x</em>₁, <em>x</em>₂, … etc. and the height of each rectangle are the corresponding <em>y </em>'s at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function <em>G(x)</em> continuous* over an interval [<em>a</em>, <em>b</em>] is equal to the slope of the secant line through <em>x</em> = <em>a</em> and <em>x</em> = <em>b</em>, i.e. the value of the difference quotient

(<em>G(b)</em> - <em>G(a)</em> ) / (<em>b</em> - <em>a</em>)

If <em>G(x)</em> happens to be the antiderivative of a function <em>g(x)</em>, then this is the same as the average value of <em>g(x)</em> on the same interval,

g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [<em>a</em>, <em>b</em>] into <em>n</em> subintervals of equal width (<em>b</em> - <em>a</em>)/<em>n</em>. Over the first subinterval, the area of a trapezoid with "bases" <em>y</em>₀ and <em>y</em>₁ and "height" (<em>b</em> - <em>a</em>)/<em>n</em> is

(<em>y</em>₀ + <em>y</em>₁) (<em>b</em> - <em>a</em>)/<em>n</em>

but <em>y</em>₀ is clearly missing in the sum, and also the next term in the sum would be

(<em>y</em>₁ + <em>y</em>₂) (<em>b</em> - <em>a</em>)/<em>n</em>

the sum of these two areas would reduce to

(<em>b</em> - <em>a</em>)/<em>n</em> = (<em>y</em>₀ + <u>2</u> <em>y</em>₁ + <em>y</em>₂)

which would mean all the terms in-between would need to be doubled as well to get

\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)

7 0
3 years ago
I need help is it A B C or D
nata0808 [166]
C because you have to think a bout how to get from y to x

3 0
3 years ago
If their were thirty cows and twenty ate chickens how many didn't?
tresset_1 [31]

Answer:

10 didn’t eat chickens

Step-by-step explanation:

30-20=10

6 0
3 years ago
Read 2 more answers
A monk crossbred plants which can have purple or white flowers and obtained 511 plants with white flowers and 337 plants with pu
Zepler [3.9K]

Answer:

For purple;

P(p) = 337/848 = 0.40

For white;

P(w) = 511/848 = 0.60

Step-by-step explanation:

Given;

Number of plants with purple flowers P = 337

Number of plants with white flowers W = 511

Total T = 337 + 511 = 848

For purple;

the empirical Probability that a plant had purple flowers P(p) is

P(p) = Number of plants with purple flowers/total number of plants

P(p) = P/T

Substituting the values, we have;

P(p) = 337/848 = 0.40

For white;

the empirical Probability that a plant had white flowers P(w) is

P(w) = Number of plants with white flowers/total number of plants

P(w) = W/T

Substituting the values, we have;

P(w) = 511/848 = 0.60

4 0
3 years ago
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