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ELEN [110]
3 years ago
9

When a fraction is reduced to lowest terms, the only factor the numerator and denominator have in common is

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer: A fraction is in lowest terms when the numerator and denominator have no common factor other than 1.

Step-by-step explanation:  The factors of 2 are 1 and 2. The factors of 4 are 1, 2, and 4. 2 and 4 share a common factor: 2.

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Simplify the following expression. <br>7^-5/6.7^-7/6. <br>1/49<br>1/14<br>14<br>49
Serggg [28]

{7}^{  - \frac{5}{6} }  \times  {7}^{ -  \frac{7}{6} }  \\  =  {7}^{ -  \frac{5}{6} -  \frac{7}{6}  }  \\  =  {7}^{  -  \frac{12}{6} }  \\  = {7}^{ - 2}  \\  =  \frac{1}{ {7}^{2} } \\  =  \frac{1}{49}
The answer is 1/49
4 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Please help me with this question!
nika2105 [10]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP! We can translate ()=2|−2|−5 to the right 3 units and up 5 units to create (). Write the equation for function g.
alisha [4.7K]

Answer:

g(x)=2\,|x-5|

Step-by-step explanation:

Recall that a horizontal translation (shift) in 3 units to the right involves directly subtracting 3 from the variable x (horizontal axis variable) , and that moving the function up 5 units involves adding to the whole function 5 units. That is:

g(x)=2\,|x-3-2|- 5+ 5\\g(x)=2\,|x-5|+0\\g(x)=2\,|x-5|

5 0
3 years ago
georges playground is shown in the diagram he wants to buy timber to put all around it so that mulch does not spread how much ti
Xelga [282]
He needs 84 ft.
Step by step explanation:
(24*2)+(18*2)
48+36
84
7 0
3 years ago
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