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Ivenika [448]
2 years ago
7

What conclusion can be made for c and e?

Mathematics
1 answer:
nadezda [96]2 years ago
8 0
B is the correct answer in edgunity I think.
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Tyler goes to the store. His budget is $125. Which inequality represents x, the amount in dollars Tyler can spend at the store?
raketka [301]

Answer:

The answer is A

Step-by-step explanation:

If Tyler's budget is $125, he cannot spend more than that. He can spend at most $125; which is represented as less than or equal to.

x \leqslant 125

6 0
3 years ago
N is the set of integers that are greater than - 3 and less than 2.
Schach [20]
The given set is {-1,0,1,2,3,4,5}
(notice the -2 and 6 are excluded)

the subset which contain positive factors of 5 is {1,5}

so the complement set would be
{-1,0,2,3,4) which matches with b)

4 0
3 years ago
A line and two points are guaranteed to be coplanar if
kicyunya [14]
The points lie on the line, I believe, since they're part of it. 
5 0
3 years ago
1.2/4.4 = 3/a what is a
bazaltina [42]
Simply cross multiply and simplify to get a = 11

Hope this helped!! xx
7 0
3 years ago
Read 2 more answers
A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
xz_007 [3.2K]

Answer:

The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).

Critical value t=1.318

Step-by-step explanation:

We have to calculate a 80% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=0.165.

The sample size is N=25.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016

The degrees of freedom for this sample size are:

df=n-1=25-1=24

The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.318 \cdot 0.016=0.021

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186

The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).

6 0
3 years ago
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