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2 years ago

A lines passes through the point (2,4) and has a slope of 4. Find the equation of the line.

Mathematics

1 answer:

Jet001 [13]2 years ago

8 0

The answer is y=4x-8, it should work

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Help me!!!! Pls ASAP

ehidna [41]

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

To get the slope you have to find the difference in Y and put it over the difference in X. (x2-x1)/(y2-y1). You plug in the points and you get -1/2

8 0

2 years ago

Read 2 more answers

Hall and Mindy are playing a guessing game. Hall tells Mindy: ""The difference between 17 and the square root of my mystery numb

cestrela7 [59]

Answer:

The possible number that Hall could be thinking of is 144.

Step-by-step explanation:

Difference between 17 and the square root of my mystery number

This is represented by:

$17 - \sqrt{x}$

is 5

Then:

$17 - \sqrt{x} = 5$

What are two possible numbers that Hall could be thinking of?

We have to solve the equation, for x. So

$17 - \sqrt{x} = 5$

$\sqrt{x} = 12$

$(\sqrt{x})^2 = (12)^2$

$x = 144$

The possible number that Hall could be thinking of is 144.

5 0

3 years ago

A rectangular garden has a length of 9 feet and a width of 4.5 feet. What is the perimeter of the garden?

Andreyy89

Answer: 27

Explanation:
P = 2(l+w) = 2 · (9 + 4.5) = 27

6 0

3 years ago

Can someone plz help plz show work

aliya0001 [1]

Answer:

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

$h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft$

The Lateral Area is the sum of the areas of three rectangles:

$4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2$

The Lateral Area:

$LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2$

8 0

3 years ago

The pH level of a solution measures how acidic or basic the solution is. Values between 0 and 7 are considered acidic while valu

Furkat [3]

Answer:

about 2.47

Step-by-step explanation:

Your calculator will tell you ...

$-\log{(3.4\times 10^{-3})}\approx 2.4685\approx\bf{2.47}$

4 0

2 years ago