From the graph, when x = 1, y = 57,000.
Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :
y = -2610.82(1) + 47860.82 = 45,250
y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22
y = 54041.5(0.9)^1 = 48,637.35
y = 10,504.6 (1.1)^1 = 11,555.06
The second equation is the closest. so try another x value to see if it is close to the Y value:
Let's try x = 14:
y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08
This is close to Y = 12,00 shown on the graph
SO the closest equitation is y = 219x^2 - 6506.78x + 59385
Answer:
C
Step-by-step explanation:
Graph f = x^2. Then the graph of g = (x + 3)^2 has the same shape, BUT its graph is that of f shifted 3 units to the LEFT. C is correct
Yes, the variable of interest is two-dimensional.
If you are making a graph about the area of a country, that is a two dimensional measurement. It would be ok to make a graph that is also 2 dimensional.
The equation of the line is 
Explanation:
The equation of the line is perpendicular to
The equation is of the form
where m=-14
<u>Slope:</u>
The slope of the perpendicular line can be determined using the formula,



Thus, the slope of the line is 
<u>Equation of the line:</u>
The equation of the line can be determined using the formula,

Substituting the slope
and the point (2,-4), we get,

Simplifying, we get,



Thus, the equation of the line is 
The table containing the data needed for this problem is attached on this answer. This data is used to determine the best fit line that is extracted from this multitude of points given. Best fit line is described as a line in which the variation of each point to the line is the minimum. We plot the data using MS Excel and is shown in the figure attached as well. We determine the trendline of the graph by the function in MS Excel. The equation of the trendline is expressed as <span>y = -26.059x + 722.63 in which the coefficient of determination, r^2 = 0.8947. </span>