Answer:
21
Step-by-step explanation:
Let x represent the number of dimes and y represent the number of nickels. The total number of coins is 37; this gives us the equation
x+y = 37
Each dime is worth ten cents, or 0.10, and each nickel is worth five cents, or 0.05. The total amount of money is given by
0.10x+0.05y = 2.65
This gives us the system

To solve this, we will use substitution. We will isolate x in the first equation:
x+y=37
Subtract y from each side:
x+y-y = 37-y
x = 37-y
Substitute this into the second equation:
0.10(37-y)+0.05y = 2.65
Using the distributive property,
0.10(37)-0.10(y)+0.05y = 2.65
3.70-0.10y+0.05y = 2.65
Combining like terms,
3.70-0.05y = 2.65
Subtract 3.70 from each side,
3.70-0.05y-3.70 = 2.65-3.70
-0.05y = -1.05
Divide both sides by -0.05:
-0.05y/-0.05 = -1.05/-0.05
y = 21
There were 21 nickels.
Answer:
3
Step-by-step explanation:
3
+
11
⋅
(
8
−
4
)
÷
(
5
+
6
)
−
4
Subtract 4 from 8
.
3
+
11
⋅
4
÷
(
5
+
6
)
−
4
Multiply 11 by 4
.
3
+
44
÷
(
5
+
6
)
−
4
Find the common denominator.
Add 5 and 6
.
3
+
44
÷
11
−
4
Write 3 as a fraction with denominator 1
.
3/
1
+
44
÷
11
−
4
Multiply 3/
1 by 11/
11
.
3/
1
⋅
11
/11
+
44
÷
11
−
4
Multiply 3/
1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
−
4
Write −
4 as a fraction with denominator 1
.
3
⋅
11
/11
+
44
÷
11
+ −
4
/1
Multiply −
4
/1 by 11
/11
.
3
⋅
11
/11
+
44
÷
11
+
−
4
/1 ⋅
11
/11
Multiply
−
4
/1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
+ −
4
⋅
11
/11
Combine the numerators over the common denominator.
3
⋅
11
+
44
−
4
⋅
11
/11
Simplify each term.
Multiply 3 by 11
.
33
+
44
−
44
⋅
11/
11
Multiply −
4 by 11
.
33
+
44
−
44
/11
Simplify the expression.
Add 33 and 44
.
77
−
44/
11
Subtract 44 from 77
.
33
/11
Divide 33 by 11
.
3
Answer:
j-4 is how you show 4 less than a number j
Answer:
You can't factor x or any number other than 1 out.
Step-by-step explanation: