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gladu [14]
3 years ago
9

Jessica cannot remember the correct order of the five digits in her id number. she does remember that the id number contains the

digits 9, 0, 3, 1, 5. what is the probability that the first four digits of jessica’s id number will all be odd numbers?
Mathematics
2 answers:
Phantasy [73]3 years ago
4 0
Well 4 out of the 5 are odd.  So the probability the first digit is odd is (4/5) since that digit is no longer available, then the probability the second digit is odd is (3/4), then for the third (2/3), then the forth (1/2).

So to find the first four being odd is (4/5)*(3/4)*(2/3)*(1/2) = 24/120 = .20
MAVERICK [17]3 years ago
3 0

Answer:

1/5

Step-by-step explanation:

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So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
{2}^{2}  \times 3 \times 5 \\ and \\  {2}^{2}  \times  {3}^{2}  \times 5 \times 7
each have two twos. both have one 5, so we know our answer will look something like
{2}^{2}  \times 5 \times other \: stuff
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

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4 0
3 years ago
2. Describe how to use the conjugate to divide 2 − i by 3 + 2i, and then find the quotient.
DaniilM [7]

Answer:

\frac{4}{13}-\frac{7}{13}i

Step-by-step explanation:

\frac{2-i}{3+2i}

Multiply and divide by the conjugate.

The conjugate is the denominator with the sign of the complex number the opposite of the denominator.

\frac{2-i}{3+2i}\frac{3-2i}{3-2i}\\ =\frac{2\times (3-2i)-i\times (3-2i)}{3^2-(2i)^2}\\ =\frac{6-4i-3i+2i^2}{9+4}\\ =\frac{4-7i}{13}\\ =\frac{4}{13}-\frac{7}{13}i

Quotient = \frac{4}{13}-\frac{7}{13}i

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8/9

Step-by-step explanation:

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Answer:

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2 years ago
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