Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
The answer is 376$ because 47 x 8.00 = 376$
Answer:
$35.50
Step-by-step explanation:
55.50-48= 7.5
2008-2005 = 3
7.5 divided by 3 = 2.5 per year
2005-2000 = 5 multipled by 2.5 = 12.5
48-12.5=35.5
X^2 + y^2 - 2x + 7y + 1 = 0
(x^2 - 2x) + (y^2 + 7y) + 1 = 0
(x^2 - 2x + 1) + (y^2 + 7y) + 1 = 0+1
(x^2 - 2x + 1) + (y^2 + 7y + 49/4) + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1-1 = 0+1+49/4-1
(x - 1)^2 + (y + 7/2)^2 = 49/4
(x - 1)^2 + (y + 7/2)^2 = (7/2)^2
The final answer is choice B
Answer:
its a symmetrical open curve formed by the intersection of a circular cone with a plane at a smaller angle with its axis than the side of the cone.
Step-by-step explanation:
