When asked to factor the trinomial , a student gives the answer (x – 7)(x + 7). Which of the following statements is true?

Find the circumference of the pizza to the nearest tenth.

mote1985 [20]

Answer:

C=2πr

r=D/2=10/2=5

C=2×3.14×5

C=31.4in

7 0

3 years ago

What is the exact value of cos (67.5° )?

Brilliant_brown [7]

Answer:

0.38268343

Step-by-step explanation:

cos( 67.5 )

Rewrite

67.5

as an angle where the values of the six trigonometric functions are known divided by 2 . cos ( 135\ 2)

Apply the cosine half-angle identity.

±

√

1

+

cos

(

135

)

2

Change the

±

to

+

because cosine is positive in the first quadrant.

√

1

+

cos

(

135

)

2

Simplify

√

1

+

cos

(

135

)

2

√

2

−

√

2

The result can be shown in multiple forms.

Exact Form:

√

2

−

√

2

Decimal Form:

0.38268343

…

6 0

4 years ago

Possible solution for 4+x+2-2x=5

MrRissso [65]

Answer:

x=1

Step-by-step explanation:

For algebra always start by rewriting it.

4+x+2-2x=5

Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.

6-x=5

Now lets get x alone and the quickest way is to subtract 6 to the other side

6-x=5

-6 -6

-x=-1

Now the two negatives cancel out as you would divide both sides by the coefficient -1 to get positive x alone. We can make this easier by just canceling out the negatives.

Your answer is

x=1

3 0

4 years ago

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the perimeter to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the Quadratic formula , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$