<img src="https://tex.z-dn.net/?f=53%20%5Ctimes%20%5Cfrac%7B8%7D%7B6%7D%20" id="TexFormula1" title="53 \times \frac{8}{6} " alt=

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Yakvenalex [24]

3 years ago

"53 \times \frac{8}{6} " align="absmiddle" class="latex-formula">
i dont know how to do it can u show me

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

Answer:

What do you want your answer in? Exact or decimal form?

Exact form: 212/3

Decimal form 70.6

Step-by-step explanation:

Cancel the common factor of 8 and 6 for 53 * 4/3. Multiply 53(4/3), 212/3. This would be the answer for the exact form, decimal form is created by dividing 212 by 3, for 70.66666--.

Anettt [7]3 years ago

3 0

53x8
____

1x6

Do that and ur answer

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Write an expression for the sequence of operations described below.

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This might look hard at first, but if you break it down into parts, it will be much easier. With that said, start with what you know. You see that the word problem says "the difference of y and 9", which means that you have to stubtract them. So, part of the equation is going to be y - 9. Now to look at the rest of the word problem. It says to divide by 3, so now you have to take what you have so far and divide that by 3. This means that you are going to have to divide the y - 9 by 3.

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We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty

maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let X = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable X is, p = 0.697.

A random sample of n = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 50 and p = 0.697.

The probability mass function of a Binomial random variable X is:

$P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...$

(1)

Compute the expected value of X as follows:

$E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9$

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56$

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of X ≥ 45 as follows:

P (X ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

$=\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006$

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. p < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

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