All categories

2 years ago

Write an expression the represents the statement "Add 9 and 3, then multiply by 6"

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

Answer:

6(9+3)

Explanation:

Add 9 and 3 which is 9 + 3

THEN multiply by 6 which is 6(9 + 3)

I put parentheses because it's sayings to add first and then multiply!

You might be interested in

George finished 10 of 25 math problems.what percent of the problems did george finish

PIT_PIT [208]

Answer:

40%

Step-by-step explanation:

So 10/25=0.4

0.4=40%

8 0

3 years ago

Read 2 more answers

Please help thanks!!

Sidana [21]

So for this, you will be doing two different multiplications: 3 x 4 and √8 x √3.

3 x 4 = 12

√8 x √3 = √24

Now our result is 12√24, however, this can be simplified. Using the product rule of radicals (√ab = √a x √b), our simplification is such:

12√24 = 12√(8 x 3) = 12√(4 x 2 x 3) = 2 x 12√(2 x 3) = 24√6

In short, the answer is 24√6, or the first option.

4 0

2 years ago

What is the value of C

disa [49]

C = 9 m the perimeter is all the sides added together you have 9 +8 that is 17 add another 9 and that equals 26 which is the perimeter.

7 0

2 years ago

Determine if A^-1 C=C A^-1 Given: A^-1 C=

ryzh [129]

CA ⁻¹ is undefined because there are more columns in A ⁻¹ than there are rows in C.

6 0

2 years ago

Read 2 more answers

Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(

Mumz [18]

The given equations are
$x(t+1)-4t \sqrt{x} =9$ (1)
$2y+4y^{3/2}=t^{3}+t$ (2)

When t=0, obtain
$x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0$

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means $\frac{dx}{dt}$ .

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means $\frac{dy}{dt}$ .

Because $\frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}$ , obtain
$\frac{dy}{dx} |_{t=0}\, = \frac{1/2}{3}= \frac{1}{6}$

Answer:
The slope of the curve at t=0 is 1/6.

3 0

3 years ago