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loris [4]
2 years ago
5

Show your work, simple translations. Will give 5 star, brainliest, and a like on your answer.

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0
Y= -4,2 I have notes
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Which of the ordered pairs below could be in this Function?
DochEvi [55]
I believe it is.... (2,2)or(4,4)
6 0
3 years ago
Nolan and his children went into a grocery store and he bought $8 worth of apples
goldfiish [28.3K]

Nolan and his children bought fruits (Apples and bananas) worth $8.

Cost of each apple and bananas are $2 and $0.40 respectively.

Let the number of bananas he bought = y

And the number of apples = x

Therefore, cost of the apples =$2x

And the cost of bananas = $0.40y

Total cost of 'x' apples and 'y' bananas = $(2x + 0.40y)

Equation representing the total cost of fruits will be,

(2x + 0.40y) = 8

10(2x + 0.40y) = 10(8)

20x + 4y = 80

5x + y = 20 --------(1)

If he bought 5 times as many bananas as apples,

y = 5x ------(2)

Substitute the value of y from equation (2) to equation (1),

5x + 5x = 20

10x = 20

x = 2

Substitute the value of 'x' in equation (2)

y = 5(2)

y = 10

Therefore, Nolan bought 2 apples and 10 bananas.

Learn more,

brainly.com/question/14951851

8 0
3 years ago
Help!!!
Arlecino [84]
The answer is 30. 5/10 is equal to 15/30
5 0
3 years ago
What is the volume of the composite figure? Round your answer to the nearest hundredth. Use 3.14 for π.
Reil [10]

Answer:

<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>

VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE

=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)

=37.68+169.56+56.52

=263.76in^3

7 0
2 years ago
Let f (x) = 3x − 1 and ε &gt; 0. Find a δ &gt; 0 such that 0 &lt; ∣x − 5∣ &lt; δ implies ∣f (x) − 14∣ &lt; ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
2 years ago
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