All categories

3 years ago

Jason has $800 more than Paul. Alex has $150 less than Jason. How much more does Alex have than Paul?

Mathematics

1 answer:

jolli1 [7]3 years ago

4 0

Hey there!!

Jason = 800 + Paul

Alex = Jason - 150

How much more does Alex have the Paul?

Let's take the equation of Alex

... Alex = Jason - 150

... Add 150 on both sides

... Alex + 150 = Jason

Now we have the equation for Jason,

... Jason = 800 + Paul , and we got Alex + 150 = Jason

... Now let's plug in the values

... Alex + 150 = 800 + Paul

Subtract 150 on both sides...

Alex = 800 - 150 + Paul

... Alex = 650 + Paul

Now we got the answer for our question :

The answer - Alex has $650 than Paul.

Hope my answer helps!!

You might be interested in

Which expressions are equivalent?

olga55 [171]

Answer:

C none of the above

Step-by-step explanation:

x + z + y

is not going to be equal to x + y - z

Its like saying 10 + 5 - 4 = 11

To 10 + 5 + 4, they are not going to be equal

4 0

3 years ago

Read 2 more answers

What is 21 X 21 ???? <br> 3 3

Sergeeva-Olga [200]

Answer: 441

Step-by-step explanation:

21 x 21 = 441

8 0

2 years ago

Read 2 more answers

Please help !!! Need fast

evablogger [386]

4x+30=90
4x = 60
x = 15

answer is B. 15

4 0

2 years ago

Read 2 more answers

The original price of a Kindle is $269.99. If a discount of 15% is given, what is the amount of the discount?

andrey2020 [161]

15% of $269.99 = 0.15 x 269.99 = $40.50 (nearest cent)

Answer: $40.50

6 0

3 years ago

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago