Answer:
Angle measurements of 35°, 35°, and 110°
Angle measurements of 40°, 60°, and 80°
Step-by-step explanation:
If you specify only the three angles, you can have an infinite number of similar triangles of different sizes.
A is wrong. There can be only one triangle in which all three side lengths are specified.
C is wrong. The angles do not add up to 180°.
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
6 snaps a minute if you multiply 9 x 6 is 54
<h2>
Put x =
I write the sum of 6x and 2x is at least 39 .</h2>
Step-by-step explanation:
We have,,
6x and 2x
To find, the value of x = ?
According to question,
The sum of 6x and 2x is at least 39
∴ 6x + 2x = 39
⇒ 8x = 39
⇒ x = 
∴ The value of x = 
Thus, put x =
I write the sum of 6x and 2x is at least 39 .
Answer:
2
Step-by-step explanation: