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3 years ago

In the diagram below segment AC is congruent to segment CE and segment BC is congruent to segment DC.

Mathematics

1 answer:

cluponka [151]3 years ago

8 0

Step-by-step explanation:

By reflection

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Solve the system using the elimination method. (3x + 4y = 6 < (2x + 3y = 3

mr Goodwill [35]

Answer:

$3x + 4y = 6 - - - (a) \\ 2x + 3y = 3 - - - (b) \\ 2 \times (a) - 3 \times (b) : \\ = > 0x - y = 3 \\ y = - 3 \\ 2x - 9 = 3 \\ 2x = 12 \\ x = 6 \\ { \boxed{x = 6}} \\ { \boxed{y = - 3}}$

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Counting by 8s Homework

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Step-by-step explanation:

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3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

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3 years ago

Read 2 more answers

A triangle has side lengths 8 cm, 15 cm, and 16 cm. Is it a right triangle? Explain.

Flura [38]

Step-by-step explanation:

no because a triangle has 3 side

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3 years ago