The point P(–4, 4) that is 
of the way from A to B on the directed line segment AB.
Solution:
The points of the line segment are A(–8, –2) and B(6, 19).
P is the point that bisect the line segment in .
So, m = 2 and n = 5.
By section formula:
P(x, y) = (–4, 4)
Hence the point P(–4, 4) that is of the way from A to B on the directed line segment AB.
<span>The Range Rule of Thumb says that the range is about four times the standard deviation. (i.e. two standard deviations to the left and two standard deviations to the right of the mean).
Given that the mean is 500 and the standard deviation is 50, then
The minimum and the maximum "usual" values are given by
Therefore, the minimun "usual" value is 400 while the maximum "usual" value is 600.
</span>
Answer:
8
Step-by-step explanation:
You need to know the length of two sides and the degree of one angle.
The equation of the line passing through those two points is y=0x+1
