3 years ago

I have another Math Brainliest

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

8.50 and 6.25

............,,...

You might be interested in

Y+ 5\6 ≤ 1/5 I don't need work. thanks

stiv31 [10]

1/5 - 5/6 = -19/30, so the answer is Y ≤ 19/30
---
Hope this helps!
==jding713==

3 0

4 years ago

1. Lisa is working with the system of equations x + 2y = 7 and 2x ‒ 5y = 5. She multiplies the first equation by 2 and then sub

Musya8 [376]

All methods are supposed to be correct in most if not all situations and it should not matter if you use a different method given the options

3 0

4 years ago

Read 2 more answers

Can anyone help me with this

yaroslaw [1]

Answer:

answer is 11 feet is the correct answer

5 0

3 years ago

Please help quickly this is timed

liberstina [14]

Answer:

the one you have selected is correct

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

3 years ago